|
|||||
|
Navigation
|
General Instructions
Submitted by gophysics on Thu, 07/24/2008 - 13:24
Hi! Can anyone provide general instructions for making the metal salt solutions (i.e. create a 0.5 M solution of your desired metal nitrate) ... or at least specific ones for making the internal standards (0.5 M Copper nitrate and 0.5 M Iron nitrate). I'm a physics teacher, so my knowledge of such things is somewhat limited. |
||||
metal recipes
Kristen,
Lets say you want to prepare 10 ml of a 0.5 M solution of metal salt. You multiply the volume in liters by the concentration which is in units of moles/liter which gives the number of moles you need. Then multiply that by the fomula weight of the metal nitrate (including the waters of hidration in the weight, lets say it is 250 g/mole) which is unually printed on the side of the bottle. This will give you the grams of metal salt to weigh out and dissolve in the 10 ml of water.
0.5 mole/L x 0.010 L = 0.005 moles
0.005 moles x 250 g/mole = 1.25 g